Y^3-3y^2+5y=5

Solution for Y^3-3y^2+5y=5 equation:

^3-3Y^2+5Y=5

We move all terms to the left:

^3-3Y^2+5Y-(5)=0

determiningTheFunctionDomain
-3Y^2+5Y-5+^3=0

We add all the numbers together, and all the variables

-3Y^2+5Y=0

a = -3; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-3)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-3}=\frac{-10}{-6}
=1+2/3
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-3}=\frac{0}{-6}
=0
$